1967 South American Championship Tournament Overview
The 1967 South American Championship stood as a premier gathering of footballing talent from across the continent. This competition brought together the region's most prominent national teams to compete for continental supremacy in a high-stakes environment.
Tournament Structure and Format
The competition was organized as a single round-robin tournament, a format where every participating nation plays every other nation exactly once. This ensured a fair distribution of matches and a clear path to determining the champion based on overall performance.
To determine the standings, a specific points system was implemented. Teams earned two points for a win, one point for a draw, and zero points for a loss.
[ไม่มีภาพประกอบ]Participating Nations
Six countries competed in the final tournament, representing the diverse footballing landscapes of South America. The participating nations were:
- Argentina
- Bolivia
- Chile
- Paraguay
- Uruguay
- Venezuela
Key Facts
- Format: Single round-robin.
- Participants: 6 South American countries.
- Win Value: 2 points.
- Draw Value: 1 point.
- Loss Value: 0 points.
| Category | Details |
|---|---|
| Participating Teams | Argentina, Bolivia, Chile, Paraguay, Uruguay, Venezuela |
| Tournament Style | Single Round-Robin |
| Points for Win | 2 |
| Points for Draw | 1 |
Frequently Asked Questions
Which countries participated in the 1967 South American Championship?
The tournament featured Argentina, Bolivia, Chile, Paraguay, Uruguay, and Venezuela.
What was the format of the competition?
The teams competed in a single round-robin tournament, meaning each country played every other participant once.
How were points awarded during the tournament?
Teams received two points for a victory, one point for a tie (draw), and zero points for a defeat.
How many teams competed in the final tournament?
A total of six national teams participated in the event.