1959 South American Championship: Tournament Structure and Participants
The 1959 South American Championship stood as a premier gathering of football talent, hosted by Argentina. This prestigious competition brought together the top national teams from across the continent to compete for regional dominance in a high-stakes environment.
Tournament Format
The competition was organized as a single round-robin tournament, a format where every participating nation plays every other nation exactly once. This structure ensured a fair assessment of skill, as no team had an advantage in the number of matches played.
To determine the standings, a specific points system was implemented:
- Two points were awarded for a win.
- One point was awarded for a draw.
- Zero points were awarded for a loss.
Participating Nations
Seven countries competed in the 1959 edition of the championship. The host nation, Argentina, welcomed six other South American powerhouses to compete in the tournament.
| Role | Country |
|---|---|
| Host | Argentina |
| Participant | Bolivia |
| Participant | Brazil |
| Participant | Chile |
| Participant | Paraguay |
| Participant | Peru |
| Participant | Uruguay |
Key Facts
- Host Country: Argentina.
- Total Participants: 7 national teams.
- Format: Single round-robin.
- Winning Points: 2 points per victory.
- Drawing Points: 1 point per tie.
Frequently Asked Questions
Which country hosted the 1959 South American Championship?
The tournament was held in Argentina.
How many teams participated in the event?
A total of seven countries participated: Argentina, Bolivia, Brazil, Chile, Paraguay, Peru, and Uruguay.
What was the tournament format?
The teams competed in a single round-robin tournament, meaning each team played every other participant once.
How were points awarded during the 1959 championship?
Teams earned two points for a win, one point for a draw, and zero points for a loss.